SAT数学备考经典模拟题训练35

>>SAT数学模拟题：SAT数学备考经典模拟题训练35

>>SAT考试辅导

· Question #1: While competing in a marathon event, John is behind Mike by 100 yards. John runs (x - 2) yards while Mike runs (x + 10) yards. What is the new distance between them?

(a) 112 yards

(b) 108 yards

(c) 102 yards

(d) 110 yards

(e) The answer is a function of x

· Question #2: What is the sum of 10% of x and 20% of 2x?

(a) 10% of x

(b) 20% of x

(c) 30% of x

(d) 50% of x

(e) 100% of x

解析

o Solution: We can reference all distances to the point where John was at the time t1, when the distance between them is 100 yards.

After John runs (x - 2) yards, he is (x - 2) yards from the reference.

After Mike runs (x + 10) yards, he is 100 yards + (x + 10) yards = (x + 110) yards from the reference.

The distance between them will be (x + 110) - (x - 2) = 112 yards.

o Answer: 10% of x is .1x.

20% of 2x = .2·2x = .4x.

The sum of 10% of x and 20% of 2x is .1·x + .4·x = .5·x. In conclusion the sum is 50% of x.

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