SAT数学备考经典模拟题训练28

>>SAT数学模拟题：SAT数学备考经典模拟题训练28

>>SAT考试辅导

· Question #5: Given the list of integers: -2, 2, 0, 6, 8, 0, -5, 9, 10, 4, which of the following statements is true?

(a) mode < median < average

(b) median < mode < average

(c) median < average < mode

(d) mode = median < average

(e) average < median < mode

· Question #6: What are the solutions x of the equation ax·a1/x = 1, x ≠ 0 and a ≠ 1?

(a) x = -1

(b) x = 1

(c) x1 = -1 and x2 = 1

(d) The equation does not have real solutions

(e) x = a

解析

o Answer: We need to rearrange the list of integers in order: -5, -2, 0, 0, 2, 4, 6, 8, 9, 10. The average will be the sum of all integers divided by the number of integers, 32/10 = 3.2

The median will be the mean of the 2 middle numbers, 2 and 4, so the median is 3.

The mode is 0, as 0 occurs the most in the list.

The correct answer is mode < median < average.

o Answer: ax·a1/x = ax + 1/x = 1 = a0

x + 1/x = 0

(x2 + 1)/x = 0

x2 + 1 = 0. This equation does not have real solutions as x2 + 1 will always be positive.

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